Is the yield of SO3 at equilibrium favored by a lowering the volume to increase the pressure or increasing the volume to lower the pressure? 2SO2(g)+O2(g)⇌2SO3(g), ΔH = -47 kcal/mol By a higher or lower temperature?
delta H is negative, the reaction is endo or exothermic?
exo
so how the temperature will affect the reaction?
you have to consider the heat of the exothermic reaction as a product of the reaction then apply the Le Chatelier Principle
2SO2(g)+O2(g)⇌2SO3(g) + heat if you increase the heat the equilibrium will move to the right or to the left?
so increase pressure and temperature?
Then if you decrease the volume and increase the pressure the system is going to decrease the number of molecules is going to be more effective collisions the reaction will move to the side that has less molecules of gas. If you decrease the pressure or increase the volume the system will go to increase the number of molecules going to the direction where are more molecules
I agree with u @Cuanchi When the pressure is increases by decreasing the volume all the molecules get compact in a smaller volume. When u have more molecules the pressure inserted by them is high, but when u have lesser no. of molecules the pressure inserted by them is lowered. As you can see, in this reaction the products side(right side ) has less no. of molecules compared to the reactant side (left side) thus the equilibrium point will shift to the right producing more of SO3 to reduce the pressure.
|dw:1444969716178:dw|
Join our real-time social learning platform and learn together with your friends!