A population is given P(t) = 2546e^(6t) where t is in years since 1986. The rate of change of the population is P'(t) = 15276e^(6t). In 1991, the population changes by 15276e^(6*5). In 1991, 50528058399494678 of the population has died. How many were born that same year (1991)?

How do I approach this problem?

Question

A population is given P(t) = 2546e^(6t) where t is in years since 1986. The rate of change of the population is P'(t) = 15276e^(6t). In 1991, the population changes by 15276e^(6*5). In 1991, 50528058399494678 of the population has died. How many were born that same year (1991)?

How do I approach this problem?

matt101 · Answer

You're given the population change - this is the NET increase in population. The net increase equals # of births minus # of deaths. You're given the net increase and the number of deaths, so use that information to solve for the number of births. For this question, the total population (given by P(t)) is not important.