A running track in the shape of an oval is shown. The ends of the track form semicircles.

A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 56 m and length of one straight edge 130 m.

What is the perimeter of the inside of the track?

(π = 3.14)

260.00 m
347.92 m
372.00 m
435.84 m

Question

A running track in the shape of an oval is shown. The ends of the track form semicircles.

A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 56 m and length of one straight edge 130 m. 

What is the perimeter of the inside of the track?

(π = 3.14)

 260.00 m
 347.92 m
 372.00 m
 435.84 m

oregonduck · Answer

attachment

oregonduck · Answer

@g-lax4

anonymous · Answer

ok one sec and i will help

anonymous · Answer

175.93 is the sides combined plus the straightaways

anonymous · Answer

first how do you find a the perimeter of a circle

oregonduck · Answer

yeah idk part of it has to do with pi but that is all i know

oregonduck · Answer

@CJDOG @g-lax4

anonymous · Answer

C=2πr

anonymous · Answer

so 2 * 3.14 * 56 (for the small half circles you combine)

anonymous · Answer

then for the middle just find the perimeter of the rectangle

anonymous · Answer

so you add 230 to the 175.93 and thats the answer