Consider the equation 3tan^2(x)-1=0.
solve for x ? find exact solutions ??
60degrees
oh yea alright solve for tan
Im still trying to figure it out really.
ah i see 2pi/3 5pi/3 is ur answer ??
\[3\tan ^{2}x=1\]
\[\tan ^{2}x=1/3\]
No its just hat i had accidentally clicked
what's the rush ?
Like I need it in the form that is on the questions, I really almost have no Idea what im doing here.
alright first we have to solve for tanx someone already solved first 2 steps
\[\huge\rm 3\tan^2(x)-1=0\] to solve for tan first add one both sides we need tan itself at left side so divide both sides by 3 \[\tan^2(x) =\frac{1}{3}\]
what would be the next step ? how would you cancel out the square from tan^2 ?
Would you separate it where it is: (tan)(tan) and cancel one making it just Tan? Like I said I'm kind of lost, so I'm not entirely sure.
let tan(x) =y \[\huge\rm y^2=\frac{1}{3}\] do you know wha would you do to cancel out the square ??? :=))
let me know if u r not sure :=))
I am not entirely sure, I am way better at english. . . I hate math.
hm alright to cancel out the square we should take `square root` square and square cancelz each other out \[\sqrt{x^2} = x\]
so take square root `both sides ` of the equal sign
ok, so it would be \[√x^2=x^2\]?
Wait
\[√x^2=√x\]
hmm no square and square cancels each other ot |dw:1445008299219:dw| this is an example btw
Join our real-time social learning platform and learn together with your friends!