Question

g(x) = 3x2 + 12x + 15
HOW DO I FIND THE AXIS OF SYMMETRY

Answer 1

@Vampirelove28

Answer 2

This might help? http://www.tiger-algebra.com/drill/3X~2-12x-15=0/

Answer 3

I think maybe?

Answer 4

I have to explain why though

Answer 5

To find the vertex, convert to vertex form by completing the square.

3x^2-12x+15
= 3 (x^2 - 4x) + 15
= 3 (x^2 - 4x + 4 - 4) + 15
= 3 {(x^2 - 2x - 2x + 4) - 4} + 15
= 3 {x(x-2) -2(x-2)} - 12 + 15
= 3 (x - 2)^2 + 3

Original vertex form is a (x - h)^2 + k where (h, k) are the co-ordinates of the vertex.
Therefore, the vertex is (2, 3).

Also, since the y co-ordinate is 3, the axis of symmetry is x = 3. and the minimum value of the quadratic equation is y = 3. [Because a > 0 the parabola is opening upwards and there is a minimum value]

Hope this helps! :)

Answer 6

Ya i think this guy has it right just use what he has...

Answer 7

Ya i think this guy has it right just use what he has...