Question

someone help plz?

Answer 1

@Jadedry

Answer 2

what is it?

Answer 3

i just need help like working it.

Answer 4

a

Answer 5

i am stuck

Answer 6

I'm finally online!

Okay, so the key to elimination is to "eliminate" individual constants.

I'll call the equations a, b and c. (From top to bottom!)

b + c =

\[(2x + 3y + 3z) + (-2x-y+z) = 2y + 4z = 2\]

a - b =

\[(-2x +2y +3z) - (-2x - y + z) = 3y +2z = 3\]

\[(3y +2z) * 2 = 6y + 4z = 6\]

\[(6y +4z) - (2y+ 4z) = 6-2 = 4\]

therefore 4y = 4

y = 1

--

using the new information.

\[a = -2x + 2 + 3z\]

\[b= -2x - 1+z\]

\[a - b = 3 + 2z = 3\]

therefore z = 0

---

Using the new information.

\[a= -2x + 2 + 0 = 0\]

\[-2x + 2 = 0\]

therefore x = 1

Answer 7

You can plug in the values of x, y and z into each equation to see if they are correct. If they are, then the plugged in values should result in the same "end numbers" (in this case, 0,-3, 5)