Question

~^.^~
check my work pweeease
medal + fan

questions below
they might be wrong because tbh I'm not good in maths so please don't be harsh :/

Answer 1

Cant be harsh? -Sigh- No jk XD

Okay lets start with 1) I get a different answer

Completing the square tells us to take the coefficient of 'x' (10) divide it by 2 and then square that...

so 10/2 = 5 and 5^2 = 25 <--

Answer 2

lol xP and OMFGGGGG thanks for the explanation.

Answer 3

Lol of course :D

Alright so hmm, let me check #2 *I'll take a bit longer to make you worry ;P

Answer 4

Hey! lol xP
Oh man I wish my math teacher had your sense of humor it would be a lot more fun to do.

Answer 5

So #2 I get something different again...so here I'm actually gonna go through the whole thing and make sure you got the process down :)

Answer 6

So we have \(\large x^2 - 8x + 5 = 0\)

So to complete the square...we need this in the form \(\large a^2 - bx = c\)

So we need to subtract 5 from both sides of this equation to make ours look like that

\[\large x^2 - 8x = -5\]

Good so far? :)

Answer 7

Yup got it so far :]

Answer 8

Cool so now...from that general equation

\[\large ax^2 - bx = c\]
**notice i forgot the 'x' up there in the previous post...oops sorry :P

Okay but from here, to complete the square, we take the coefficient of the 'x' *which is 'b' here* ...divide it by 2...and then square the result

So in your equation

\[\large x^2 - \color \red{8}x = -5\]

8 is the coefficient we want to work with...so 8 divided by 2 = 4....and 4 squared = 16

And with that 16...we add that to both sides of our equation

\[\large x^2 - 8x + 16 = -5 + 16\]

Still good? *stop me if you need it, I'm here for ya xP

Answer 9

Ohhhhhhhhhh oh my I think I'm starting to see what I did wrong.
Still good! :]

Answer 10

Awesome :D

Okay so now lets simplify a bit

\[\large x^2 - 8x + 16 = 11\]

right?

We can write that left hand side a little simpler right?

\[\large (x - 4)^2 = 11\]

Are you good with that?

Answer 11

So it's either the first or the second answer? and yup I'm good with that. :]

Answer 12

Haha oh jumping the gun huh ;P

Lets finish up

\[\large (x - 4)^2 = 11\]

Now we just take the square root of both sides

\[\large \sqrt{(x - 4)^2} = \sqrt{11}\]

Becauseeeeeee that cancels out the

\[\large (x - 4)\cancel{^2}\]

So now we have

\[\large x - 4 = \pm\sqrt{11}\]

And finally that gives ussssssssss....?

Answer 13

The first one? O.O

Answer 14

Hey hey hey no! :P

Solve for 'x'

\[\large x - 4 = \sqrt{11}\]

Add 4 to both sides

\[\large x = 4 \pm \sqrt{11}\]

Answer 15

Ohhhh omg darn but thanks for explaining! xP

Answer 16

Haha well I mean...you were close ;D had a 50 50 chance :P

Answer 17

Haha thanks!

Answer 18

For 3) ...I seem to get a different answer again

Sheesh I need a break, lets get dinner quick ;D XDDDDD jk jk haha

okay 3

\[\large f(x) = 2(x - 1)^2 + 3\]

WE need to focus on exponents first here

\[\large 2(x - 1)(x - 1) + 3\]

Lets do all the multiplication next

\[\large 2(x^2 - 2x + 1) + 3\]
\[\large 2x^2 - 4x + 2 + 3\]
\[\large 2x^2 - 4x + 5\]

Answer 19

Oh man I would love some dinner count me in ^.^
Ah oh gosh I'm seeing so many of my mistakes lol but I really appreciate you correcting and showing me how it's really done.

Answer 20

Awesome, reservations are at 8 so you got time x)

Alright #4 I'm gonna make you do over again and let me know what you get ;P

Answer 21

lmao so in o.O I'm hungry.
Btw I'm working on it right now.

Answer 22

I am too, that's why dinner is perfect

Good food, awesome company...I'm golden XD

Answer 23

Oh you're too sweet lol xP
So I got f(x) = (x+2)^2-5 but I'm not confident about my answer :/

Answer 24

What if I told you the fate of dinner was relying on the confidence of that answer? xP

Because you are absolutely












Correct!!!!! :DDDD :D :D <3 XD

Answer 25

OMFG I cannot believe it!! I literally read the first thing and was like "oh no dinner for me" xP
Yay omg thank you so much!

Answer 26

Haha nope you're perfect!!! :D

lol have more confidence in your answers though, you're very smart :)

Answer 27

That's truly so sweet of you thank you! :]

Answer 28

Of course

Alright, I must head to work now

I'll pick ya up at 8 x) <3

Lol nice to meet you though, have a good day :)

Answer 29

Haha! Thank you so much and it was a pleasure meeting you too.
Good luck with work! :] Bye, you have a good day too.