Question

Please help with this math question, attached beow

Answer 1

e to the x is its own derivative

Answer 2

use the power rule for the second one

Answer 3

Hint:
\[\Large \frac{2}{\sqrt[3]{x}} = \frac{2}{x^{1/3}}\]
\[\Large \frac{2}{\sqrt[3]{x}} = 2*\frac{1}{x^{1/3}}\]
\[\Large \frac{2}{\sqrt[3]{x}} = 2*x^{-1/3}\]

Answer 4

would it be that be the answer?
@jim_thompson5910

Answer 5

no, that helps you when it comes to using the power rule @satellite73 mentioned

Answer 6

Power Rule:

if `y = x^n`, then `dy/dx = n*x^(n-1)`

Answer 7

would the answer be 6e^x + 2/ 2x^-1/3 ? @jim

Answer 8

@jim_thompson5910

Answer 9

the first step when it comes to using the power rule is to pull down the exponent of -1/3