Find the values of x and y that make these triangles congruent by HL. A. x = 2, y = 2 B. x = 4, y = 4 C. x = 5, y = 5 D. x = 3, y = 3 Will medal and fan if correct!!!! :)
no diagram, but set the corresponding legs or angles equal to form some equations to solve
for 2 variables, need 2 equations
Sorry there is a diagram, I forgot to add it. One sec
Seems like you got help :D Goodluck!
ok, what does "by HL " mean ?
By Hypotenuse-Leg Theorem
oh, ok Two triangles ABC and AED the corresponding parts are congruent (the same)
Right
They already give you that BC = ED, those two dashes mean same
That is first equation BC = ED y = x
My second equation is 2x + 3 = 3y + 1
right, y = x and 2x + 3 = 3y +1
But I don't know what to do next. :(
the first equation tells you that y=x, you can replace y in the second by y=x, x 2x + 3 = 3y + 1 2x + 3 = 3x + 1
If y = (something) You can replace y with all the (something) anywhere in the other equation, to reduce to one variable
you good? on solving that now?
I think the answer is either A or B. When checked on the calc they both answers for x and y are the same.
yes they have to be, remember the first equation , y = x
Ik, I mean A, the equations both equal 7, but for B. they both equal 13, but C and D are different answers. Thus leaving A and B.
the first equation tells you that y=x, you can replace y in the second by y=x 2x + 3 = 3y + 1 2x + 3 = 3x + 1 you can now solve that for x, after replaceing y by y=x 2x + 3 = 3x + 1
3x - 2x = 3 - 1 x = 2
I got it! Thanks that helped a lot!!
welcome, if they dont give you y = x, but y = 5x + 3,. just put the 5x+3 in for y and solve, Substitution then use that value in either original equation to calculate the other variable
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