Question

Probablity question

Answer 1

\(\large \color{black}{\begin{align}
& P(A)=0.5,P(A\cap B)=0.3 \hspace{.33em}\\~\\
& \normalsize \text{ Is it possible that}\ \large P(B)=0.9 \hspace{.33em}\\~\\
& a.)\ \normalsize \text{No} \hspace{.33em}\\~\\
& b.)\ \normalsize \text{Yes} \hspace{.33em}\\~\\
& c.)\ \normalsize \text{Either}\ (a.)\ \text{or}\ (b.) \hspace{.33em}\\~\\
& d.)\ \normalsize \text{Can't Say} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

if a and b are independent then
p(a and p)= p(a).p(b)
0.3=0.5* p(b)
p(b)=0.6
which give us the idea that a and be are not independent

Answer 3

what u mean

Answer 4

means there should be s conditional case which i'm thinking what it should be xD

Answer 5

wwhich option is corect

Answer 6

i would rather to say it's possible, if we looked for a condition which would take a property of 3/9 <1 could make p(b)=0.9 then it's accurate :)

Answer 7

for ma i'd say option b.yes

finger crossed xD

Answer 8

Clearly the maximum probability for event B is 1-0.2 = 0.8

this is achieved only if there are no other possible events

Answer 9

hmmm

Answer 10

so with the given conditions, we have \(P(B)\le 0.8\)

Answer 11

But in book max P(B)=0.6

Answer 12

the question is not about finding P(B)
it is about finding the maximum possible value of P(B)

Answer 13

I think, we can say this much : \(0.3\le P(B)\le 0.8\)

idk how your book got 0.6 hmm

Answer 14

it gives P(A\(\cap\)B)=P(A)*P(B)

Answer 15

take a screenshot and attach if psble

Answer 16

wait