The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 15 terms of the arithmetic progression?
we can write these formulas: \[\begin{gathered} {a_4} = {a_1} + 3d \hfill \\ {a_{12}} = {a_1} + 11d \hfill \\ \end{gathered} \] where \(a_1,a_4,a_{12}\) are the first, the fourth and the twelft terms of your progression, and \(d\) is the constant of progression
using your condtition we get: \[{a_4} + {a_{12}} = 2{a_1} + 14d = 20\] or: \[{a_1} + 7d = 10\]
finally we can write: \[\begin{gathered} {S_{15}} = \frac{{{a_1} + {a_{15}}}}{2} \cdot 15 = \frac{{{a_1} + {a_1} + 14d}}{2} \cdot 15 = \hfill \\ \hfill \\ = \frac{{2{a_1} + 14d}}{2} \cdot 15 = \left( {{a_1} + 7d} \right) \cdot 15 = 10 \cdot 15 = ...? \hfill \\ \end{gathered} \]
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