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7,3,2 The proof is on the way
\[=x^2(x-7)-5x(x-7)+6(x-7)=(x-7)(x^2-5x+6)=(x-7)(x-2)(x-3)\]
the zeros are given by x-7=0,x-2=0,x-3=0 i.e. x=2,3,7
@iwanttogotostanford
That definitely works @jango_IN_DTOWN or you could (more easily) substitute in the x-values and see if it results in a zero. The zero of a function is the value of x such that f(x)=0. If you plug in the various x-values, you can quickly see whether or not it results in a zero for this function. While this is not a "proof," it is nonetheless a quick way of dispatching a multiple choice problem of this nature.
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