Question

A 2.9 kg brick has a kinetic coefficient of friction of 0.33. what force must be applied to the brick for it to move at a constant velocity

Answer 1

By the first principle of Newton, we have to apply a force with the same direction and magnitude of the friction force, and with an orientation opposite with respect to such friction force

So, \(F=R=\mu \cdot m \cdot g=...\)
where \(\mu=0.33\), \(m=2.9\) Kg, and \(g=9.81 \) m/sec^2