Question

Please help!! pulley problem with kinematics!! help!! http://prntscr.com/8sfrnx

Answer 1

@Mehek14 do you think you can do this?? please help

Answer 2

i would help you but im not good with physics

Answer 3

haha its ok @MariahDimond mom do you know how to do this? @momo2001

Answer 4

No sorry

Answer 5

\(\large\color{black}{ \displaystyle \rm T=m{~}\cdot{~}g =3{~}\color{grey}{kg}\times9{~}\color{grey}{m/s^2} }\)

Answer 6

NOTE:
The other mass of 3kg (the upper 3kg block) doesn't exert any force on
that string between the two 3kg blocks.

Answer 7

@SolomonZelaman can you prove that? According to you all the 3kg objects should be free falling under the gravity and 7kg is not affecting any of the object. And also if that s so, 7kg object should be rising at the acceleration of 'g'

Its obvious that \(T_2 = T_3\) (because its a frictionless pulley)

Id first assume that two 3kg as a one system with 6kg



for 3kg+3kg system -> \[\begin{align}
\downarrow F&= ma \\
6g-T&= 6a
\end{align}\]
do the same for 7kg ->\[\begin{align}
\uparrow F&= ma \\
T-7g&= 7a
\end{align}\]

from this you can find the acceration and the tension \(T_1 , T_2\)

To find the tension between two 3kg object apply F=ma again to one of the 3kg objects
(id recommend the lowest one)