Question

WILL FAN AND MEDAL!
multiple choice;)

Answer 1

You have a piece-wise function with three parts:

\(\LARGE\color{black}{ f(x) = \begin{cases} & x+14,{~~~~~~}{\large x<-7} \\ & 21,{~~~~~~~~~~~~~~}{\large -7\le x<-6} \\ & x^2-1,{~~~~~}{\large -6\le x} \end{cases} }\)

Answer 2

To which of the three pieces does \(\color{blue}{x=6}\) belong to,


1) x<-7
2) -7≤x<-6
3) -6≤x

Answer 3

can you tell me that please?

Answer 4

I believe option 3?

Answer 5

yes, x=6 belongs to `-6≤x`

Answer 6

I meant which peace does x=-6 belong to

Answer 7

yeah!

Answer 8

but you agree that it is still the third on, because only `-6≤x` contains x=-6, right?

Answer 9

Apologize for typos...
anyway,

that means that you have to use \(x^2-1\) peace to evaluate f(-6)
ie, you plug in x=-6 into \(x^2-1\) to find f(-6)

Answer 10

wouldnt that make it 21?

Answer 11

are you sure?

Answer 12

no wait tis 8 right? agh

Answer 13

\(f(-6)=(-6)^2-1=?\)

Answer 14

11? sorry mybrains dead

Answer 15

(-6)² = (-6) • (-6) = ?

Answer 16

6 times 6 is 36, and when you have two negatives in there the negatives become positive.

Answer 17

35

Answer 18

yes

Answer 19

thank ya:)

Answer 20

yw