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Mathematics 17 Online
OpenStudy (anonymous):

WILL FAN & MEDAL!

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Are you familiar with the idea that \[\Large \left(g \circ f\right)(x) = g(f(x))\]

OpenStudy (anonymous):

I was not:

jimthompson5910 (jim_thompson5910):

are you able to determine the value of `f(6)` ?

OpenStudy (anonymous):

no...:-/

jimthompson5910 (jim_thompson5910):

in f(x), replace every x with 6 and evaluate

jimthompson5910 (jim_thompson5910):

\[\large f(\color{red}{x}) = 2(\color{red}{x}) - 8\] \[\large f(\color{red}{6}) = 2(\color{red}{6}) - 8\] \[\large f(6) = ??\]

OpenStudy (anonymous):

4?

OpenStudy (anonymous):

oh i was looking at the wrong question haha, does that make it -6?

jimthompson5910 (jim_thompson5910):

\[\Large \left(g \circ f\right)(x) = g(f(x))\] \[\Large \left(g \circ f\right)(\color{red}{x}) = g(f(\color{red}{x}))\] \[\Large \left(g \circ f\right)(\color{red}{6}) = g(f(\color{red}{6}))\] \[\Large \left(g \circ f\right)(6) = g(f(6))\] Since f(6) = 4, we can replace the "f(6)" with "4" \[\Large \left(g \circ f\right)(6) = g(f(6))\] \[\Large \left(g \circ f\right)(6) = g(\color{red}{f(6)})\] \[\Large \left(g \circ f\right)(6) = g(\color{red}{4})\]

jimthompson5910 (jim_thompson5910):

now you just need to evaluate g(4). This is similar to how we evaluated f(6)

OpenStudy (anonymous):

6?

jimthompson5910 (jim_thompson5910):

plug x = 4 into the g(x) function

OpenStudy (anonymous):

im getting six...

jimthompson5910 (jim_thompson5910):

g(x) = x-5 g(4) = 4-5 ... replace every x with 4 g(4) = ???

OpenStudy (anonymous):

omg -1...

OpenStudy (anonymous):

right?:D

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

yep -1

OpenStudy (anonymous):

thanks youre awesome!:DDD

jimthompson5910 (jim_thompson5910):

you're welcome

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