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Mathematics
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OpenStudy (anonymous):
WILL FAN & MEDAL!
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
Are you familiar with the idea that
\[\Large \left(g \circ f\right)(x) = g(f(x))\]
OpenStudy (anonymous):
I was not:
jimthompson5910 (jim_thompson5910):
are you able to determine the value of `f(6)` ?
OpenStudy (anonymous):
no...:-/
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jimthompson5910 (jim_thompson5910):
in f(x), replace every x with 6 and evaluate
jimthompson5910 (jim_thompson5910):
\[\large f(\color{red}{x}) = 2(\color{red}{x}) - 8\]
\[\large f(\color{red}{6}) = 2(\color{red}{6}) - 8\]
\[\large f(6) = ??\]
OpenStudy (anonymous):
4?
OpenStudy (anonymous):
oh i was looking at the wrong question haha, does that make it -6?
jimthompson5910 (jim_thompson5910):
\[\Large \left(g \circ f\right)(x) = g(f(x))\]
\[\Large \left(g \circ f\right)(\color{red}{x}) = g(f(\color{red}{x}))\]
\[\Large \left(g \circ f\right)(\color{red}{6}) = g(f(\color{red}{6}))\]
\[\Large \left(g \circ f\right)(6) = g(f(6))\]
Since f(6) = 4, we can replace the "f(6)" with "4"
\[\Large \left(g \circ f\right)(6) = g(f(6))\]
\[\Large \left(g \circ f\right)(6) = g(\color{red}{f(6)})\]
\[\Large \left(g \circ f\right)(6) = g(\color{red}{4})\]
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jimthompson5910 (jim_thompson5910):
now you just need to evaluate g(4). This is similar to how we evaluated f(6)
OpenStudy (anonymous):
6?
jimthompson5910 (jim_thompson5910):
plug x = 4 into the g(x) function
OpenStudy (anonymous):
im getting six...
jimthompson5910 (jim_thompson5910):
g(x) = x-5
g(4) = 4-5 ... replace every x with 4
g(4) = ???
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OpenStudy (anonymous):
omg -1...
OpenStudy (anonymous):
right?:D
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
yep -1
OpenStudy (anonymous):
thanks youre awesome!:DDD
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jimthompson5910 (jim_thompson5910):
you're welcome
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