Triiodide ions are generated in solution by the following reaction: IO3-(aq)+I-(aq)-I3-(aq). Triiodide ion is determined by titration with a sodium thiosulfate (Na2S2O3) solution. The products are iodide ion and tetrathionate ion (S3O62-).
a. Balance the equation for the reaction of IO3- with I- ions.
b. Write and balance the equation for the reaction of S2O32- and I3-.
c. A 25.00 ml sample of a 0.0100 M solution of KIO3 is reacted with an excess of KI. It requires 32.04 ml of Na2S2O3 solution to titrate the I3- ions present. What is the molarity of the Na2S2O3 solution?
d. How would..

Question

Triiodide ions are generated in solution by the following reaction: IO3-(aq)+I-(aq)->I3-(aq). Triiodide ion is determined by titration with a sodium thiosulfate (Na2S2O3) solution. The products are iodide ion and tetrathionate ion (S3O62-). 
a. Balance the equation for the reaction of IO3- with I- ions. 
b. Write and balance the equation for the reaction of S2O32- and I3-. 
c. A 25.00 ml sample of a 0.0100 M solution of KIO3 is reacted with an excess of KI. It requires 32.04 ml of Na2S2O3 solution to titrate the I3- ions present. What is the molarity of the Na2S2O3 solution?
d. How would..

anonymous · Answer

cont. ... you prepare 500.0 ml of the KIO3 solution in part c, using pure dry KIO3?

anonymous · Answer

ok i did the first one for now. hope it's right,., i'll try the rest tomorrow ! it's late here ;w; 
a. IO3- + 8I- + 6H+ -> 3I3- + 3H2O

anonymous · Answer

b. I3- + 2(S2O3)2- -> I3- + (S4O6)2-
c. 0.0416M Na2S2O3  ?
d. idk what pure dry KIO3 would do , . ,