Select the equation of the line that passes through the point (2, 6) and is perpendicular to the line x = 4. y = 4 y = 6 x = 6 x = 2
y = 6......because x = 4 is a vertical line (it goes up and down)...and if you want a perpendicular line that goes through 6 on the y axis....then it would be y = 6. I am not real good at explaining this stuff...
NNesha....can you explain this better ?
understand this....when you have y = a number, then it is a horizontal line (going across) and if you have x = a number, then it is a vertical line (going up and down)
Its ok i kinda get it
Ready for the next one? here you go
slope of vertical line is undefined doesn't matter what number we get at the numerator but denominator would always be zero so let's say slope of vertical line \[\large\rm m = \frac{ 3 }{ 0 }\] and slope of perpendicular will be negative reciprocal flip the fraction and change the sign \[\rm m= -\frac{0}{3}\] ^^^^^^^ slope of perpendicular line plug that into the original equation \[\large\rm y=mx+b\] m is slope and b is y-intercept substitute x and y order pair for (2,6) \[\rm 6=-\frac{0}{3}(2)+b\] 0 times anything = same thing so \[\rm b=\color{red}{6} \rightarrow y=\color{reD}{b} \rightarrow y=\color{ReD}{6}\]
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