Question

the numbers in this sequence increase by 7 each time.
1,8,15,22,29....
the sequence continues in the same way. will the number 777 be in this sequence? YES/NO
Why?

Answer 1

it is arithmetic progression

Answer 2

no

Answer 3

first term a=1
common difference =8-1 =7
d=7

Answer 4

No because
1+111 X 7= 1=777=778
8+111 X 7= 8=777=785 785-7=778
It's one more than 777
So, the solution is NO. Hope it helps you.

Answer 5

last term =777 (which is have to check)

Answer 6

lol I already said no

Answer 7

a+(n-1)d =777
1+(n-1)7 =777
he needs explanation

Answer 8

No Any number in the series minus 1 should be divisible by 7,Like 29-1=28, 22-1=21 but 777-1=776 not divisible by 7!

Answer 9

very good,
best concept

Answer 10

The difference between numbers is 7, hence the general formula for it is \(a_n = 1+ 7(n-1) = 7n -6\)
if 777 is in the sequence , then 777 = 7n -6, n = 771/7 = 110.1428 which is not integer.
Hence 777 is not in the sequence.