Question

MEDAL!

A polling organization conducts a poll by making a random survey of 1500 people. Estimate the margin of error at a confidence level of 95%. Round your answer as a percentage to two decimal places.

Answer 1

Sure, ill help.

Answer 2

Okay, :) use the "margin of error Forumula" When you report the results of a statistical survey, you need to include the margin of error.

p is the sample proportion , n is the sample size, and z* is the appropriate z*-value for your desired level of confidence (from the following table).

z*-Values for Selected (Percentage) Confidence Levels
Percentage Confidence z*-Value
ex:
80 1.28
90 1.645
95 1.96
98 2.33
99 2.58
Note that these values are taken from the standard normal (Z-) distribution. The area between each z* value and the negative of that z* value is the confidence percentage (approximately). For example, the area between z*=1.28 and z=-1.28 is approximately 0.80. Hence this chart can be expanded to other confidence percentages as well. The chart shows only the confidence percentages most commonly used.

Here are the steps for calculating the margin of error for a sample proportion:

Find the sample size, n, and the sample proportion.

The sample proportion

p is the number in the sample with the characteristic of interest, divided by n.

Multiply the sample proportion by
1-p
Divide the result by n.

Take the square root of the calculated value.

You now have the standard error,
:)

Answer 3

@ikileyxx