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OpenStudy (anonymous):
OpenStudy (anonymous):
\[\cos \theta=0\]
OpenStudy (anonymous):
I got \[\cos \theta=1\]
OpenStudy (anonymous):
-2 +(1/3)cos Θ = -5/3
(1/3) cos Θ = 1/3
cos Θ = 1
then you have to go to the unit circle and find Θ where the x-coordinate is 1.
OpenStudy (anonymous):
Thanks
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OpenStudy (anonymous):
would it be 2pi? as a radical
OpenStudy (anonymous):
it would be 0 and 2pi
OpenStudy (anonymous):
it depends on your interval. I what you put above is right (both < signs) then there's no solution. If one of them is ≤, use that one
OpenStudy (anonymous):
0 ≤theta<2pi
OpenStudy (anonymous):
so it would be 0
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OpenStudy (anonymous):
yes 0
OpenStudy (anonymous):
can i ask another question ? for another problem?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
sin(theta)=2
OpenStudy (anonymous):
and how do you know where to look at the x or y axis for the unit circle?
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OpenStudy (anonymous):
based on which trig function you're working with.
(x, y) = (cos Θ, sin Θ)
so cos Θ is the x and sin Θ is the y.
OpenStudy (anonymous):
and tan?
OpenStudy (anonymous):
If you notice, the radius of the unit circle is 1. that's also the range of both cos Θ and sin Θ. Neither can be more than 1.
sin Θ = 2 has no solution
OpenStudy (anonymous):
\[\tan\theta=\frac{ \sin \theta }{ \cos \theta }=\frac{ y }{ x }\]
OpenStudy (anonymous):
Thank you thats everything
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