smallville college has 8 faculty, 6 of whom are tenured. the chairman wants to establish a committee of 3 faculty members to review the curriculum. if she selects the committee at random: a) what is the probability all members of the committee are tenured? b) what is the probability at least one member is not tenured?
a. The total number of ways to choose 3 members out of 8 is C(8, 3) = 8!/(3! 5!) = (8*7*6*5*4*3*2*1) / ((3*2*1) * (5*4*3*2*1)) =? The total number of ways to choose 3 tenured people from 6 is C(6,3) = 6!/(3! 3!) = (6*5*4*3*2*1) / ((3*2*1) * (3*2*1))=? This is not my work i found it here: http://www.justanswer.com/calculus-and-above/6i4nu-computer-systems-department-eight-faculty-six-whom.html I wanted to help you but I did not know this stuff so once again this is NOT my work.
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