Question

???

Answer 1

hint: look at the derivative of the exponents there

Answer 2

which integrals do you have the following form after subbing the exponent as u:
\[\int\limits K e^{u} du \\ \text{ where } K \text{ is a constant }\]

Answer 3

A and c

Answer 4

should be A and B have that form
since (x^2)'=2x and (2x+3)'=2

Answer 5

Oh okay I see

Answer 6

\[\int\limits x e^{x^2} dx \\ u=x^2 \\ du=2x dx \\ \frac{1}{2} du =x dx \\ \int\limits \frac{1}{2} e^{u} du \text{ is the first integral after subbing the exponent }\]



\[\int\limits e^{2x+3} dx \\ u=2x+3 \\ du=2 dx \\ \frac{1}{2} du =dx \\ \int\limits \frac{1}{2} e^{u} du \text{ is the second one after the subbing the exponent }\]

Answer 7

in the last one those (x^2)'=2x and we have x^2 next to that e^(x^2) thingy

Answer 8

that last can not be solved with a simple sub

Answer 9

Thank you!