Question

Trying to figure out if im doing this right? Let f(x)=-5x+3 and g(x)=x^2-2x+1

f(-3)=
g(-x)=
f(4m-2)=
g(x+2)=


Please Help me understand

Answer 1

\[\large\rm f(\color{reD}{-3}) \rightarrow \color{reD}{x=-3}\] f(-3) means x = -3
so just substitute x for -3 into the f(x) function
ssame steps for other 3 :=))]

Answer 2

So I got 18 for the first one but the others are confusing my professor just gave it to us and is due in the am

Answer 3

huh ohhh professor :P
alright
like i say same steps for
g(-x) :=))
what you should plug into the g(x) for x ?

Answer 4

\[\large\rm f(\color{reD}{-x}) \rightarrow \color{reD}{x=??}\]

Answer 5

See I don't. Understand it would just be a negative x right no number makes it a little harder

Answer 6

ye just replace `x` with `-x`
\[\rm g(\color{reD}{-x}) =\color{Red}{x}^2-2\color{reD}{x}+1\]

Answer 7

remember when we take even power of a negative number/variable u will get positive answer :=))

Answer 8

to find g(x+2) substitute x for x+2 \[\large\rm f(\color{reD}{x+2}) \rightarrow \color{reD}{x=(x+2)}\] \[\huge\rm g(\color{red}{x+2})= \color{ReD}{x}^2-2\color{ReD}{x}+1\]
\[\large\rm g(\color{red}{x+2})= \color{ReD}{(x+2)}^2-2\color{ReD}{(x+2)}+1\]
for this one (x+2)^2 is same as (x+2)(x+2 )multiply them using foil method
and distribute (x+2) by -2
at the end just combine like terms

same steps for number 3
try it!!! :=))

Answer 9

Whats the answer for f(4m-2)

Answer 10

what did you get ??
f(4m-2) is easier thang(x+2) :=))
substitute x for `4m-2` into f(x) function

Answer 11

3 what's the answer