Find the total area of the frustum of a regular square pyramid which is inscribed in the frustum of a cone whose upper and lower base diameters are 4ft. and 6ft.,respectively, and whose altitude is 12ft. I know that the answer is 196, but when I'm solving it i got 156.06.. I don't know why..
The four slant edges of the truncated pyramid will be touching the cone within which it is inscribed. Thus, the diameter of the cone at some height is equal to the diagonal of the square pyramid. If you know the diagonal of a square, then what are the side lengths? Once you have the side lengths of the top and bottom of the truncated pyramid, you know the area of the top and bottom, the square portions. What shape are the sides of the truncated pyramid? How can you find their areas?
Austin is good at math lol
Listen to him hes always right
Most of it
Not Statistics
the sides of the top square is\[\frac{ 4 }{ \sqrt{3} } \] and the lower square is \[\frac{ 6 }{ \sqrt{3} } \] so the area of the top is 16/3 and the lower is 12
lol ok UnicornPoopCookies :)
Austin come help me ill give you a medal -____-
In the picture is that your work of the Area
I need to help Dan first if I'll be able to help him or not. @UnicornPoopCookies
yes @Austin1617 ... and i think there is something wrong but i can't find it :( thanks
Surface Area or Area
I keep using different formula but getting different answers lol
Are you sure its 196?
Nvm
lol.. not really but i saw it on the net and its in the choices of the question
Now i'm checking your work
Do you have to show work?
yes :(
I dont understand how you got \[\frac{ 4 }{ \sqrt{3}} and \frac{ 6 }{ \sqrt{3} }\]
I want someone else to do this problem and see what i'm doing wrong.
oh wait
or unless you messed up and i can't notice it
whats the "oh wait"
i use the \[\sqrt{3} \] instead of \[\sqrt{2}\]
to get the diagonal of square u need to multiple the side to \[\sqrt{2}\]
YESSSSS
sorry
you fixed your own problem :D
hahaha I'm always like that
I was confused about the \[\sqrt{3}\]
but there you go
do you have anymore questions you need help on?
none thanks anyway :))
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