Question

Help i always give metals ;)

When simplified, what is the value of square root of negative 128 end square root, if i^2 = −1?

Answer 1

well making the substitution you get

-128 = 128i^2

which can be written as 2 x 64 x i^2

now you should be able to simplify it

Answer 2

hmm is it

Answer 3

\[\sqrt{-128}\]
whenever u see negative sign separate that from the number\[\sqrt{-1 \times 128}\]
now use the fact \[i=\sqrt{-1}\]
and as mentioned above
128 can be written as 2 times 64\[\sqrt{-1 *2*64} \rightarrow \sqrt{-1} *\sqrt{64}*\sqrt{2}\]