Question

Decompose -2x-23/2x^2-9x-5 into partial fractions

Answer 1

\[\frac{ -2x-23 }{ 2x ^{2}-9x-5}\]

Answer 2

i got \[\frac{ -3 }{ 2x+1 }+\frac{ 4 }{ x-5}\]

Answer 3

How's it going

Answer 4

??

Answer 5

What I can't help you? I helped you before?

Answer 6

yes, i gave my answer

Answer 7

Its almost right

Answer 8

When you use the system of equations, you find the coefficients of the partial fractions.
A=-3
B=4

You switched your x-5 and 2x+1 equations and your A answer with -3

Answer 9

So it would actually be

\[-\frac{ 3 }{ x-5 } + \frac{ 4 }{ 2x+1 } instead of \frac{ -3}{ 2x+1 } + \frac{ 4}{ x-5 }\]

Answer 10

i see where i went wrong, this really helped out a lot. thank you, sorry i didn't mean to seem rude earlier. i appreciate your help.

Answer 11

No problem. Need any more help with any other questions you have?

Answer 12

yes. im trying to solve this one
\[\frac{ 14 }{ x ^{2}-3x }\]

Answer 13

What kind method was provided

Answer 14

wait it didnt go right..

Answer 15

\[\frac{ 14 }{ x ^{2}-3x }-\frac{ 8 }{ x } >\frac{ -10 }{ x-3 }\]

Answer 16

i got -19 <x<3 as a result

Answer 17

Was there a certain method with it or is it decompose

Answer 18

decompose

Answer 19

You almost got that one right. You will be determining the given intervals to make each factor positive or negative. If the number of negative factors is odd, then the entire expression over this interval is negative. If the number of negative factors is even, then the entire expression over this interval is positive.

x<-19 makes the expression NEGATIVE
-19<x<0 makes the expression POSITIVE
0<x<3 makes the expression NEGATIVE
3<x makes the expression POSITIVE

Since this is a greater than 0 inequality, all intervals that make the expression positive are part of the solution.

-19 <x<0 or x>3

Answer 20

Hows that?

Answer 21

makes sense :3 im not too good with math and i usually make small mistakes. thank you

Answer 22

Nice cat pictures btw.

Answer 23

Medal for that lol :D