find dy/dx assume r, s, and t are constants

rx^2 - sy^2 = t^2

i keep on getting ((2t-2xr)/2ys), but it is wrong, any help?

Question

find dy/dx assume r, s, and t are constants 

rx^2 - sy^2 = t^2

i keep on getting ((2t-2xr)/2ys), but it is wrong, any help?

zepdrix · Answer

Ah I see the problem! :)

zepdrix · Answer

Hint: Your final answer shouldn't include any t in it.

If t is a constant, then $\large\rm \frac{d}{dx}t^2=0$
No power rule for him!

anonymous · Answer

i did (2-2xr)/(2ys) and its still wrong :/

zepdrix · Answer

Yah that doesn't look right.
Hmm..

zepdrix · Answer

Did you apply product rule to the (r)(x^2) maybe?

zepdrix · Answer

$$\large\rm r x^2-s y^2=t^2$$Differentiating with respect to x should give you,$$\large\rm 2rx-2syy'=0$$Any confusion on that?

anonymous · Answer

ok i understand that

zepdrix · Answer

Solve for y'
:)

anonymous · Answer

Yes! that was right, so why was that right though?

zepdrix · Answer

Quote Benitob:
`ok i understand that`

So clearly you don't understand that derivative if you're asking this question XD lol

zepdrix · Answer

Umm I guess it's because .. chain rule?
It's hard to say, I'm not sure what mistakes you were making in your problem.