Question

Quadratic equation...

Answer 1

\[\large \color {blue}{k^2 - 12 = 10k}\]

Answer 2

@jim_thompson5910

Answer 3

do you solve for k? or?....

Answer 4

I got the answer of \(5 \pm 2\sqrt{3}\)

Answer 5

Yes you solve for k

Answer 6

alright give me a sec.

Answer 7

Do you want me to explain too?

Answer 8

Can you just say whether my answer was correct or not?

Answer 9

it's incorrect

Answer 10

It's not correct

Answer 11

Now you can explain

Answer 12

did you find your a, b ,and c function to put it into the quadratic formula?

Answer 13

Okay wait.. gimme a moment

Answer 14

Sorry would the answer be:
\[5 \pm \sqrt{13}\]

Answer 15

no

Answer 16

Nope

Answer 17

I don't understand

Answer 18

do you know the quadratic formula and get your right functions to put it into the formula?

Answer 19

@calculusxy what is the value of `b^2 - 4ac` in this case?

Answer 20

I got the equation as:
\[k^2 - 10k - 12 = 0 \]

Answer 21

\[\frac{ 10 \pm \sqrt{100 - 4(-12)} }{ 2 }\]

Answer 22

\[k=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a}\]

Answer 23

That's what I got after I put it in the quadratic formula

Answer 24

what is 100-4(-12) equal to?

Answer 25

a=1, b=-10, c=-12

Answer 26

yes

Answer 27

\[\frac{ 10 \pm \sqrt{52} }{ 2 }\]

Answer 28

100-4(-12) = 100+48

NOT

100-4(-12) = 100-48

Answer 29

OH okay ...

Answer 30

so i got \[5 \pm \sqrt{37}\]

Answer 31

same here

Answer 32

thank you!

Answer 33

Yeah.

Answer 34

I was busying putting in my equation