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Find relative extrema of 7x^2+6x-6 using the second derivative test.
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really you can't possibly need any derivative to find the max or min of a parabola
min is at the second coordinate of the vertex the first coordinate of the vertex is \(-\frac{b}{2a}\) and the second is what you get when you plug in that number
in any case your second derivative i is a constant, namely 14 meaning the parabola is concave up which you knew already because the leading coefficient is positive
Okay thank you!
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