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Mathematics 14 Online
OpenStudy (shes.radical):

Quick Question...

OpenStudy (shes.radical):

How does \[x^3+2x^2-9x-18\] turn into \[x^2(x+2)-9(x+2)\] and then into \[(x^2-9)(x+2)\]

OpenStudy (shes.radical):

I just don't understand how the first equation turns into the second .-.

OpenStudy (shes.radical):

@Michele_Laino

OpenStudy (michele_laino):

we have to factor out \(x^2\) between the first and second terms furthermore, we have to factor out \(-9\) between the third and fourth terms

OpenStudy (michele_laino):

at the final step, we have to factor out \((x+2)\)

OpenStudy (shes.radical):

okay...but why (x+2) ?

OpenStudy (michele_laino):

since \((x+2)\) is the common factor

OpenStudy (shes.radical):

from \[x^2(x+2)-9(x+2)\] how get x+2 from x^3+2x^2 ?

OpenStudy (michele_laino):

here we have: \(\left( {x + 2} \right)\) is contained as a factor in the term \({x^2}\left( {x + 2} \right)\) furthermore: \(\left( {x + 2} \right)\) is also contained as a factor into the term \(9\left( {x + 2} \right)\) so \(\left( {x + 2} \right)\) is a common factor, and I can factor out it

OpenStudy (shes.radical):

i know. i dont get HOW you got x+2

OpenStudy (michele_laino):

now if I apply the distributive property of multiplication over addition, I get this: \[{x^2}\left( {x + 2} \right) = {x^2} \cdot x + 2 \cdot {x^2}\]

OpenStudy (michele_laino):

furthermore, if I apply the same property, I can write this: \[ - 9\left( {x + 2} \right) = - 9x - 2 \cdot 9\]

OpenStudy (michele_laino):

finally, if we add the right sides of the two expressions above, I get your original expression

OpenStudy (shes.radical):

...alright i guess. what i understand is that: \[x^3 \] and \[2x^2\] have \[x^2\] in common. which leaves x+2 left over. is THAT where the (x+2) comes from? if so, why is it also combined with -9?

OpenStudy (michele_laino):

starting from the expression below: \[{x^2}\left( {x + 2} \right) - 9\left( {x + 2} \right)\] I can factor out the quantity \((x+2)\), so I get this: \[\left( {x + 2} \right)\left( {{x^2} - 9} \right)\]

OpenStudy (shes.radical):

wipe out the last equation. just totally forget about it. im talking about: why is it -9(x+2)? where did the (x+2) come from? i understand the x^2(x+2)...but why -9(x+2)?

OpenStudy (michele_laino):

because I factored out \(-9\) between the third and fourth term of your original expression, like this: \[ - 9x - 18 = - 9\left( {x + 2} \right)\]

OpenStudy (shes.radical):

...I guess I get it...alright well thanks anyway

OpenStudy (shes.radical):

wow...omg i completely get it now xD sorry for the hassle and THANK YOU FOR YOUR PATIENCE!!

OpenStudy (michele_laino):

:)

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