Question

Verify the identity.

cotx minus pi divided by two. = -tan x

Answer 1

oh it's negative so it should be

Answer 2

oh well that's not right wait plz

Answer 3

cot = cos /sin right
so it we can write \[\large\rm \frac{ \cos (x -\frac{\pi}{2} )}{ \sin{ x - (\frac{\pi}{2} )}}\]

Answer 4

cot = cos /sin right
so it we can write \[\large\rm \frac{ \cos (x -\frac{\pi}{2} )}{ \sin{ (x - \frac{\pi}{2} )}}\]

Answer 5

ohh ok

Answer 6

\[\large\rm \cos(a-b)= \cos a \cos b + \sin a \sin b\]
and \[\large\rm \sin(a-b)= \sin a \cos b - \cos a \sin b\]

Answer 7

(cos x)(cos π2) + (sin x)(sin π2)
(sin x)(sin π2) - (cos x)(cos π2)

Answer 8

\[\cot \left( x-\frac{ \pi }{ 2 } \right)=\cot \left\{ -\left( \frac{ \pi }{ 2 }-x \right) \right\}\]
\[=-\cot \left( \frac{ \pi }{ 2 }-x \right)=-\tan x\]

Answer 9

so is = (cos(x−(π/2)) = (cos x)(cos π2) + (sin x)(sin π2) wrong

Answer 10

nvm for somereason i thought have to solve left side instead *Verify *

Answer 11

we*

Answer 12

what should i write then?

Answer 13

just cot(x−π2)=cot{−(π2−x)}

=−cot(π2−x)=−tanx

Answer 14

yes bec \[\cot(\frac{\pi}{2} -x) =\tan(x)\] is an identty

Answer 15

identity **