Find the measure of angle x. Round your answer to the nearest hundredth. (please type the numerical answer only)
hmm, which class is this for?
Geometry
So lets see, have you used trig before? like sin, cos?
a little bit
Okay good, that makes it easier then...and it's very easy I'll explain step by step
So we have a triangle |dw:1445434069149:dw|
Notice that we have an angle that we want....as well as 2 sides of the triangle known In reference to the angle...we know the side opposite that angle.....and we also know the side adjacent to the angle...right?
yes
So think back to your trig functions sine cosine tangent Which one of those uses those sides? the opposite and adjacent?
cosine?
Not quite There is a VERY easy way to remember which functions require which sides Remember SOH-CAH-TOA S sine O opposite H hypotenuse C cosine A adjacent H hypotenuse T tangent O opposite A adjacent So sin = opposite / hypotenuse cos = adjacent / hypotenuse tan = opposite / adjacent
Ohh okay
Now I know you're like wtf why would that help? how will I remember that? turn it into a sentence Like Some - Old - Horse - Caught - Another - Horse - Tripping - Over - Apples Haha or something corny like that XD
So now you see that \[\large \tan(x) = \frac{opposite}{adjacent} = \frac{8}{15}\] right? now there is only 1 more step
okay, I'm starting to understand
So since we have \[\large \tan(x) = \frac{8}{15}\] We need to solve for 'x' *notice we are solving for tan(x) there* how would we solve for just 'x'? Well if you've noticed...every trig function (sin, cos, tan) also has an inverse function (arcsin, arccos, arctan) And what we see is that if we take the inverse function, of the function...they cancel i.e. \[\large arctan(tan(x)) = x\] So it seems with our \(\large tan(x) = \frac{8}{15}\) if we just take the arctan of both sides, we can solve for 'x' \[\large x = arctan(\frac{8}{15})\] Plugging that into any calculator **************in degrees mode****************** will give you your angle :)
so would my answer be 2.128
Not quite That might be in radians *that's why I tried to emphasize that the calculator has to be in degrees mode before you do the calculation Because what I get is \[\large \arctan(\frac{8}{15}) = 28.07 \text{ Degrees}\]
okay, thank you!
No problem! I hope it made sense :)
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