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Physics 22 Online
OpenStudy (daniellelovee):

at what point on the position-time graph shown is the object's instantaneous velocity smallest

OpenStudy (daniellelovee):

OpenStudy (daniellelovee):

@Directrix @kropot72

Directrix (directrix):

Look at the graph. What is going on to the immediate left of point D? What is going on to the immediate right of point D? By "going on," I mean with regard to velocity.

OpenStudy (daniellelovee):

20,50?

OpenStudy (daniellelovee):

D=50/20=2.5

OpenStudy (daniellelovee):

nvm I figured it out I just had to do the velocity formula which would give me F :)

Directrix (directrix):

As best I remember, at point D, the instantaneous velocity is zero. This is a conceptual rather than computational question, to my thinking.

OpenStudy (daniellelovee):

but velocity is m/s therefore D would be the biggest point

OpenStudy (mathmate):

@daniellelovee Velocity is dy/dx, or the rate of change of x. On a "curved line" velocity-time graph, velocity is the slope of the tangent line. The slope of the tangent line is zero (i.e. tangent line is horizontal) at both D and F, which means that the velocities are both zero. So both D and F are valid answers for zero instanteneous velocity, and both are correct answers IF the question asked for the minimum \(speed\). Since velocity is a signed quantity, so the smallest velocity will mean the "most negative velocity", or the "most negative" slope of the tangent line, which I believe (visually) occurs at E (assuming it is not a kink.)|dw:1445425151450:dw|

OpenStudy (mathmate):

|dw:1445425266875:dw|

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