Question

Tom and wingspan are running the same race , the probablity
of their winning are 1/5 and 1/2 respectively. Find the
probablity that either of them will win the race.

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{ Tom and wingspan are running the same race , the probablity }\hspace{.33em}\\~\\
& \normalsize \text{ of their winning are 1/5 and 1/2 respectively. Find the }\hspace{.33em}\\~\\
& \normalsize \text{ probablity that either of them will win the race.}\hspace{.33em}\\~\\
& a.)\ \dfrac{7}{10} \hspace{.33em}\\~\\
& b.)\ \dfrac{3}{10} \hspace{.33em}\\~\\
& c.)\ \dfrac{1}{5} \hspace{.33em}\\~\\
& d.)\ \dfrac{7}{9} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

CAN YOU UNBLOCK ME PLEASE

Answer 3

Since they are in same race, notice that, they cannot both win the race at the same time. So the events are mutually exclusive

Answer 4

Events:
T=tom wins
W=wingspan wins

Probability of either one of them winning is the probability of the union of the two events, \(T\cup W\), and the probability is
P(\(T\cup W\))=P(T)+P(W)-P(\(T\cap W\))

if we assume events T and W are mutually exclusive (i.e. they cannot be cochampions), then
P(\(T\cap W\))=0, and
P(T∪W)=P(T)+P(W)-0 = ?

Answer 5

\(\large \color{black}{\begin{align}
& P(A\cup B)=P(A)+P(B) \hspace{.33em}\\~\\
\end{align}}\)