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Find the limit of the function algebraically.
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is the answer -7?
One way to evaluate the limit is to substitute the value \(x\) is approaching, in this case: \[ \lim_{x \to 0} \frac{-7+x}{x^2} = \frac{-7+0}{0^2} = \frac{-7}{0}\] Note that \( \frac{-7}{0}\) is undefined in the real numbers so the limit does not exist. Note further that this is only true for limits that approach \( \frac{k}{0} \) where \(k \neq 0 \). If your limit approaches \( \frac{0}{0} \), this is an indeterminate form and the answer is inconclusive (more analysis is necessary).
thanks so much that's very helpful
you're quite welcome
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