Question

Use the quadratic formula to solve the equation.
-4x^2-3x+2=0

Answer 1

we have to rewrite your equation like this:
\[4{x^2} + 3x - 2 = 0\]

Answer 2

after that, we have to apply this formula:
\[x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]
where \(a=4,b=3,c=-2\)
Please try

Answer 3

\[x=\frac{ -3\pm \sqrt{-23} }{8}\]
So would it look like this?

Answer 4

I got this:
\[x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}} = \frac{{ - 3 \pm \sqrt {9 + 32} }}{8} = \frac{{ - 3 \pm \sqrt {41} }}{8}\]

Answer 5

So it looks like I messed up some how in that one section, so can you explain how you got that?

Answer 6

step by step:
\[\sqrt {{b^2} - 4ac} = \sqrt {{3^2} - 4 \cdot 4 \cdot \left( { - 2} \right)} = \sqrt {9 + 32} = \sqrt {41} \]

Answer 7

oh I see what I did wrong okay minor mistake. Okay so what next do I do?

Answer 8

so, we have these solutions:
\[{x_1} = \frac{{ - 3 + \sqrt {41} }}{8},\quad {x_2} = \frac{{ - 3 - \sqrt {41} }}{8}\]

Answer 9

ok

Answer 10

:)