Question

y > 2x^2+4x + 6
how do i provide 2 ordered pairs which satisfy the quadratic inequality?? Please Help!!

Answer 1

ok

Answer 2

do you know how?

Answer 3

if you plug in something like `x = 0` into `y = 2x^2 + 4x + 6`, what value of y do you get?

Answer 4

i was goin to say thet

Answer 5

there is the answer

Answer 6

It Has to be less than zero

Answer 7

which is why im confused?

Answer 8

Ordered pair solutions to equations - Khan Academy
Video for y > 2x^2+4x + 6 how do i provide 2 ordered pairs which satisfy the quadratic inequality?

Answer 9

look at the vid it will help

Answer 10

Okay Hold On

Answer 11

This is inequalities not equations

Answer 12

oh sorry

Answer 13

Sorry I got distracted

Replace every x with 0

y = 2x^2 + 4x + 6
y = 2*0^2 + 4*0 + 6
y = 6

so the ordered pair (0,6) is on the graph of y = 2x^2 + 4x + 6

what you can do is simply bump up the y coordinate to get to (0,7). This point is guaranteed to be in the solution region because the shaded solution region is above the parabolic curve

Repeat these steps for other x values like x = 1, x = 2, etc