How would I solve -5|6y+22|<70
Is this correct? -70<-30y-110<70
I saw your reply for just a second then it vanished.
@ybarrap don't be afraid to help.
When I solved my equation, I got -4/3>y>-6
Hero...am I right?
OK...thinking
Divide by -5 on both sides and then flip the inequality sign to face the other direction since you are dividing by a negative number. Then subtract 22 on both sides and last divide by six. With absolute value inequalities, you will need to set up two inequalities with one having -70 and with the inequality sign pointing towards the opposite direction and the one that you got after you divided by -5
I think that's what I did. I got for the answer: -4/3>y>-6
you set up the two equations after isolating the absolute value
i mean inequalities
-70<-5|6y+22|<70
1st rewrite: $$ -5|6y+22|<70\\ \sqrt{(6y+22)^2}>(-70/5) $$
DSS, so what you got is correct
I'm confused
Then expand $$ (6y+22)^2>(-70/5)^2\\ (6y+22)^2-(-70/5)^2>0\\ 36y^2+264y+288>0 $$ Using quadratic formula you can find where the function equal zero. Since this function curves upward, you then know that on either side of these zeros, the function is positive: $$ y>-4/3\\ y<-6 $$
I got y<-4/3 & y>-6
In the 1st step when you divide by -5 you need to flip the inequality
ok
OK...I see. thanks for your help.
you're welcome
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