Adrian must choose between two long distance plans. Plan a charges a monthly fee of $15, plus $0.07 per minute one every long-distance call. Plan b charges a monthly fee of $50 for unlimited long- distance calss ( that is, no cost per minute). How many minutes of long-distance calls would it take for the two plans to cost the same @CGGURUMANJUNATH
First we need to put plan A into an equation....
ok?
So how would you put it into an equation?
i don't really know, i been working on this question for an hour, i couldn't figured it out
Well I'll explain it as best as I can.... First we must put plan A into an equation so... it says that they pay $15 per month "plus" $0.07 per minute of calling soooo....the plus indicates that we are going to add.... \[15 + ? = ?\] We also know of how much they pay per minute which is $0.07 but we dont know is the total minutes so we input this...\[15 + 0.07x \] This is the equation for plan A... Do you get it?
do we equal two equations together a=b
and then solve??
Yup! We will simplify the equation but the setup is this...\[15 + 0.07x = 50\] 50 is for plan A... do you know how to simplify this equation?
i got 500 is that right?
Correct! So it would take 500 minutes of calling to get equal costs!
thank you so much for helping me! i really appreciate it! but i have one more last one! will you help me with it? :)
Sure!
the sum of two integers is 131. the larger integer is 8 more than twice the samller integer. find the two inegers
i did 2x+8=131 and then i subtracted both sides by 8 i got 123 divide by 2
i got 61.5 and then i subtracted 131-61.5 to find the other integer
did i do it right?
Yup! Your process is correct! I would have done that way as well xD
thank u so much :)
Np xD Glad to Help! "Thank you" for asking the question xD
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