Use substitution to solve the system.
I just want to know if this is a correct answer. @Nnesha
Anybody? Please.
work please :=)) or explain how did you get the answer :=) to check the answer you can substitute -99 for x and -17 for y in both equation :=))
\[-5y=\frac{ -14-3x }{ -5 }\]
\[y=\frac{ 14 }{ 5 }+\frac{ 3 }{ 5 }x\]
oh wait a sec look at 2nd equation `y=2x+7` so just substitute y for 2nd equation
they already solved 2nd equation for y
alright \[3x-5(2x+7)\]
looks good and that's equal to -14 \[3x-5(2x+7)=-14\] same steps just like we did on a previous post :=)
okay... 3x-10x-35=-14 -7x-35=-14 -7x=21 x=-3
correct?
perfecT!!
okay so then whats y? Sorry
substitute x for -3 in 2nd equation :=))
okay wait wouldn't y be equal to one
that's what i got :=)) nice job!
okay thank you :)
lets check the answer \[\rm 1=2(-3)+7~~~~ 1=1\] substitute x and y value in both equation if you get equal sides then your answer is correct \[3(-3)-5(1)=-14~~~~~~~-14=-14\] (-3,1) worked out for both equation os yes it's correct
np :=))
yes it did :)
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