Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (marcelie):

help please !!! how do i solve this i got stuck... i attach a picture below ..

OpenStudy (marcelie):

OpenStudy (marcelie):

what should i do next ?

OpenStudy (anonymous):

What are you required to proof?

OpenStudy (anonymous):

I can't understand

OpenStudy (anonymous):

\[\frac{\cot(t)+\tan(t)}{\sec(-t)}\] What is required to do with expression?Do you need to prove it equal to something?Are you required to simplify it?

OpenStudy (anonymous):

Also the identity you've written on the right side of your paper is slightly wrong, it should be \[\tan^2(x)+1=\sec^2(x)\] Another extremely useful identity you can use here is \[\sec(-x)=\sec(x)\]

OpenStudy (marcelie):

yes.

OpenStudy (marcelie):

how did sec become sec (x ) ?

OpenStudy (anonymous):

\[\sin(-x)=-\sin(x)\]\[\cos(-x)=\cos(x)\]\[\tan(-x)=-\tan(x)\]\[\csc(-x)=-\csc(x)\]\[\sec(-x)=\sec(x)\]\[\cot(-x)=-\cot(x)\] These are all important identities, have you learned them yet?

OpenStudy (marcelie):

no

OpenStudy (marcelie):

odd and even functions

OpenStudy (anonymous):

Yep, cosine and secant are even functions, so cos(-x) and sec(-x) will be cos(x) and sec(x) respectively

OpenStudy (marcelie):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
15 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
18 hours ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Arizona: does anyone know the percentage rate of 30,000 and 40,000
1 week ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!