Question

Match each pair of points with the coordinate that will make a right triangle with its hypotenuse along the graph shown.

First-quadrant graph showing a ray through the origin and the points (1, 2), (2, 4), (3, 8), and (4, 8).
Column A Column B
1.
(1, 2) and (2, 4)
2.
(2, 4) and (3, 6)
3.
(2, 4) and (4, 8)
4.
(1, 2) and (3, 6)
A.
(3, 2)
B.
(3, 4)
C.
(5, 6)
D.
(2, 2)
E.
(4, 4)

Answer 1

points are at (1,2) (2,4) (3,6) (4,8)

Answer 2

@mathmate could you help?

Answer 3

So is the third point (3,6) or (3,8)? You indicated (3,8) in the first paragraph.

Answer 4

*second paragraph

Answer 5

no on the graph the points are (1,2) (2,4) (3,6) (4,8)

Answer 6

Do you know what is the condition that two lines are perpendicular?

Answer 7

how do I attach the file so I can show you the graph

Answer 8

Nevermind I got it

Answer 9

You don't need to, I'll draw it.

Answer 10

r u sure

Answer 11

it just showed the arrow and it was going sideways... and going up it the numbers were (1,2) (2,4) (3,6) (4,8)

Answer 12

yes but with out the black lines

Answer 13

So there, you need to figure out the coordinates of the vertex of each of the right angles that I drew.

Answer 14

The black (vertical and horizontal) lines are the hints I give you.
You will need to figure the coordinates of the points where the angle is a right angle.
For example, for the right triangle joining points (1,2) and (2,4), the coordinate of the third vertex is (2,2).

Answer 15

so number 1 is D and 2 is B 3 is E and 4 is A

Answer 16

I don't work with letters, I only work with the actual values.
Please translate the A, B ... into the actual values. I can check those for you if you do.

Answer 17

im just going with what i think... i think im right

Answer 18

It's up to you.
If you say (1,2), (2,4) and (2,2) form a right triangle, you will notice something and learn from it.

Answer 19

ok I'll tell you what I get

Answer 20

I got 100% yay!!

Answer 21

Congrats, you got 100% without learning what they want you to learn.

Answer 22

what do you mean

Answer 23

thats how i was suppose to do it i was confused so I looked in my book and it explained it