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Mathematics 67 Online
OpenStudy (anonymous):

Find the area of the figure. Assume the figure is made up of parallelograms and triangles. A. 441 cm² B. 343 cm² C. 539 cm² D. 686 cm²

OpenStudy (hyperlunatic):

Didn't you already answer the question?

OpenStudy (anonymous):

OpenStudy (anonymous):

no

OpenStudy (anonymous):

@Nnesha

Nnesha (nnesha):

what's the formula to find area of right triangle ? do you know ?

OpenStudy (anonymous):

no

Nnesha (nnesha):

it's okay alright formula to find area of right triangle is \[\large\rm A=\frac{1}{2}b*h\] and to find area of parallelogram \[\large\rm A= b*h\]

Nnesha (nnesha):

base = b height = h

Nnesha (nnesha):

|dw:1445526348534:dw| find the area of both figrue and then to get the final result add area of right triangle + area of parallelogram

OpenStudy (anonymous):

14*21=294 28*14=392 294+392=686

Nnesha (nnesha):

hmm area of right triangle is base times height divided by 2 bec of the fact parallelograms can be divided into two right triangle

Nnesha (nnesha):

14 times 21 =294 now divide it by 2

OpenStudy (anonymous):

147

Nnesha (nnesha):

right now add them that would be the final answer

OpenStudy (anonymous):

147+?

Nnesha (nnesha):

`area of right triangle + area of parallelograms `

OpenStudy (anonymous):

343

Nnesha (nnesha):

hmm no what's the area of parallelograms ?

Nnesha (nnesha):

it's not 343 ...

Nnesha (nnesha):

\(\color{blue}{\text{Originally Posted by}}\) @pinkydots 14*21=294 28*14=392 294+392=686 \(\color{blue}{\text{End of Quote}}\) 392 is correct for the rea of parallelograms add it with 147

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