Question

Limit as x approaches infinity of (16x/(4x+9))

Answer 1

I.e \[\lim_{x \rightarrow \infty} \frac{ 16x }{ 4x+9 }\]

Answer 2

divide numerator and denominator with x
plz ,do it

Answer 3

Apply L'Hopital's Rule.
16x/4x=4
Answer: 4

Answer 4

r u there

Answer 5

Ahh right

Answer 6

Sorry, got disconnected
But I see it now, both L'Hopitals Rule and Dayakar's method, (16x/(4x+9)) = 16/(4 + 9/x) --> 9/x approaches 0 as x approaches infinity --> the expression approaches 16/4 = 4. Thanks guys! Damn, really out of shape mathematically..