~Line Integral question~
How do I calculate it when I am only given an f x ds? What is X? is x the function, or the value of a function?
is it f(x) = x, or an unknown function arbitrarily called x?
this looks simple, in the x-y plane so for the first bit, you have y =x, so dy = dx for the other parts, either dx or dy will be zero
Cleanup to avoid confusion. is the "x" in the integral x ds a function or the contents of a function? So is it g(x) = x --> Integral g(x) ds ?
|dw:1445549912256:dw|
the C on the integral means it is a closed loop... so |dw:1445550129801:dw|
there are a number of things that this can mean for instance, the line from 0,0 to 1,1 means y = x, so dy = dx
I have no problem with that part - my part is understanding the integral x ds. I could probably solve it if they havent written than confusing integral x ds. If I erase the line that says "integral x ds" I could figure out the functions of all three lines. Does integral x ds have any importance here, or is it just there to tell me that this is an line integral (scalar field? Conservative field?) ?
i think that is right
ds means scalar arc length
What does x symbolize? A coordinate or function that we have to parametrize ourselves?
x is x, ie the x coordinate in xy space
Sorry for not responding in a long time - Openstudy have issues that prevents the page from loading :( Thank you for your help! I have received my answer. Making a new post for new questions instead of asking multiple questions in one post :)
No - in this context, \(x\) is the integrand and must therefore be parameterized. To be clear, I'll actually do the integral. The parameterizations are as follows - I'll diagram the first one for clarity.|dw:1445556615477:dw| Segment 1: (0,0) \(\rightarrow\) (1,1) Let \(x(s) = \frac{s}{\sqrt{2}}, s\in [0,\sqrt{2}]\) Segment 2: (1,1) \(\rightarrow\) (1,0) Let \(x(s) = 1-s, s\in [0,1]\) Segment 3: (1,0) \(\rightarrow\) (0,0) \(x(s) = 0\), so we can just forget this part
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