A group of students are going on a field trip. If the group takes 3 vans and 1 car, 22 students can be transported. If the group takes 2 vans and 4 cars, 28 students can be transported. How many students can fit in each van? Can someone show me how to solve this please?
let x be the number of people that fit in a van and y be the number that fit in a car then 3 vans and 1 car, 22 students means 3x + y =22 2 vans and 4 cars, 28 students means 2x +4y=28 you have two equations and two unknowns do you know how to solve this ?
Do I have to add the equations together some how?
@phi
there are two ways to solve these. Substitution or elimination I usually use elimination (as that is how you solve 3 equations and 3 unknowns) 3x + y =22 2x +4y=28 the first thing to notice is that we can divide the 2nd equation by 2 (that means both sides and all terms) to get x + 2y = 14 that makes it a little simpler
3x+ y= 22 x + 2y = 14 Next, I would multiply the first equation by -2 (that means both sides and all terms are multiplied by -2)
I am confused on where the -2 came from, and is there some sort of steps to follow in equations like these? Like first divide, then multiply then... I feel like I'm missing something
@phi
when you have two equations like 3x+ y= 22 x + 2y = 14 and want to (for example) "get rid of the y", I notice that if the top equation had a -2y then when we add the two equations (term by term) the -2y+2y would add up to 0 (cancel out) so let's multiply the top equation by -2 (that means multiply both sides and all terms by -2) can you do that ?
you should get -6x+ -2y = -44 for the 1st equation x + 2y = 14 now add term by term -5x + 0 = -30 or 5x=30 x=6
thank you for your help, I really don't understand but I will keep looking over what you've said and try to understand how you got where you did
If you have time, see https://www.khanacademy.org/math/algebra-basics/core-algebra-systems/core-algebra-systems-tutorial/v/solving-systems-of-equations-by-multiplication
this video is making a lot of sense to me thank you! The other videos answer some of my other questions as well.
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