Question
^^
solve \(n+4=9\) for \(n\) in one step
\[\frac{8^{n}}{y^{-4}}=8^{n+4}=8^9\] making \(n+4=9\)
thats confusiing
yes, i know, this question is confusing rather silly too when you divide, you subtract the exponents so \[\frac{8^?}{8^{-4}}=8^{?+4}\]
you know the answer is \(8^9\) cause that is what it says that means \(?+4=9\) so \(?=5\)
the check is that \[\frac{8^5}{8^{-4}}=8^{5-(-4)}=8^{5+4}=8^9\] as needed
honestely i still dont get it
i know i sound dumb im sorry but math is hard for me
yeah i don't really know any other way to say it though it is a question about properties of exponents, but it is asked in a strange way
here is what you are supposed to know when you divide, you subtract the exponents
so for example \[\frac{8^{10}}{8^4}=8^{10-4}=8^6\]
and \[\frac{8^5}{8^{-4}}=8^{5-(-4)}=8^9\]
Ohhhh so its 10 -4=6
right in my example, not in your question though
oh :/
in your question you had to fill in the blank for the exponent in the top
so you had to think of a number that, when added to 4, gives 9 that number is 5
oh
that makes since.
Join our real-time social learning platform and learn together with your friends!