Question

A deck of cards consists of four suits of 13 cards each for a total of 52 cards. Each suite has an ace, king, queen, jack, and then the numbers 2 through 10. When playing a basic game of blackjack, a player is dealt two random cards. The values of these cards are then added together with face cards (jack, queen, and king) being worth 10 each, aces being worth either 1 or 11 based on the players choice, and all other cards worth their face value. The player then must decide whether to draw additional cards or not to try to get their total to 21. The player closest to 21 without going over 21 wi

Answer 1

A deck of cards consists of four suits of 13 cards each for a total of 52 cards. Each suite has an ace, king, queen, jack, and then the numbers 2 through 10. When playing a basic game of blackjack, a player is dealt two random cards. The values of these cards are then added together with face cards (jack, queen, and king) being worth 10 each, aces being worth either 1 or 11 based on the players choice, and all other cards worth their face value. The player then must decide whether to draw additional cards or not to try to get their total to 21. The player closest to 21 without going over 21 wins. Using all 52 cards, how many distinctly different starting hands of two cards could be dealt?

Answer 2

@freckles

Answer 3

i think after all the verbiage, all you are asked is how many ways there are to choose two cards out of a deck of 52, i.e. 52 choose 2

Answer 4

do you know how to compute "52 choose " sometimes written as \[\binom{52}{2}\] or \[_{52}C_2\] or even \[^{52}C_2\]?

Answer 5

@satellite73 i know that c = n/(n-r)!r!

Answer 6

it wouldn't be (13x4)(12x4) would it? since there are simply 2 cards?

Answer 7

@satellite73