Use π = 3.14. Determine the area and perimeter of the figures below. (Use π = 3.14. Round your answers to two decimal places.)Assume that a = 12 m, b = 10 m, c = 16 m, and d = 20 m.
@DelTaVsPi
Okay this one should be fine to solve as well. So I hope that you've also notice that this shape is comprised of two smaller shapes, a rectangle and a right-angled Triangle
Like always, we'll solve area first!
So like previously, I'm going to split the diagram into two smaller areas; Area 1 and Area 2 We are going to solve for Area 1 first and that's the rectangle :)
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The area of the rectangle is A = Length x Height
So A = 12 x 20 = 240 Units Squared
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Area 2 will be that small right-angled Triangle
So it will be A = 1/2 x (4)(10) = 20 Units Squared
so 260= area
Thus we can add the two areas together now, like so: A = Area 1 + Area 2 = 20 + 240 = 260 units squared
now perimeter
Okay the perimeter
The perimeter is almost solve, although he have to find this really small side first using Pythagoras formula first
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x^2 = 10^2 + 4^2 = 100 + 16 x = Sqrt[116] = 10.77 Units
So now since we have solved this smaller side, we can now add all the other sides together now! P = 12 + 20 + 16 + 10.77 + 10 = 68.77 Units
that is correct. thank you
Cool :)
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